The oxidation number of the underlined atom i | vedclass

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(B) $(1) \ HAuCl_4 \Rightarrow (+1) + x + 4(-1) = 0, x = +3$ $(2) \ Cu_2\underline{O} \Rightarrow 2(+1) + x = 0, x = -2$ $(3) \ \underline{Cl}O_3^{-}

Vedclass · Accepted Answer

$Cu_2\underline{O}$ is $-1$

Vedclass · Answer

(B) $(1) \ HAuCl_4 \Rightarrow (+1) + x + 4(-1) = 0, x = +3$ $(2) \ Cu_2\underline{O} \Rightarrow 2(+1) + x = 0, x = -2$ $(3) \ \underline{Cl}O_3^{-} \Rightarrow x + 3(-2) = -1, x = +5$ $(4) \ K_2\underline{Cr_2O_7} \Rightarrow 2(+1) + 2x + 7(-2) = 0, x = +6$ The oxidation number of oxygen in $Cu_2O$ is $-2$,not $-1$. Therefore,option $B$ is incorrect.

The oxidation number of the underlined atom in the following species is given. Identify the incorrect option.

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